Primary exercises
- Manually created factor.
In a study participants were asked whether their sport activity is none, oncePerWeek, severalPerWeek or daily.
Build a proper factor for the responses below and store it in a variable w.
Print the factor.
Write the code to count the numbers of occurrences of each level and print the counts.
severalPerWeek, none, none, oncePerWeek, oncePerWeek, oncePerWeek, oncePerWeek, ?, none, none
v <- c( "severalPerWeek", "none", "none", "oncePerWeek", "oncePerWeek", "oncePerWeek", "oncePerWeek", NA, "none", "none" )
w <- factor( v, levels = c( "none", "oncePerWeek", "severalPerWeek", "daily" ) )
w
[1] severalPerWeek none none oncePerWeek oncePerWeek oncePerWeek oncePerWeek
[8] <NA> none none
Levels: none oncePerWeek severalPerWeek daily
fct_count( w )
# A tibble: 5 x 2
f n
<fct> <int>
1 none 4
2 oncePerWeek 4
3 severalPerWeek 1
4 daily 0
5 <NA> 1
- A factor with a random content.
Read help about the function sample.
Then study and try the following lines of code to understand the results.
Next, understand why an error is generated and use replace argument to generate a vector with 100 samples.
Store this vector in a variable v and build a factor w from it.
Finally, count the numbers of occurrences of each level in w.
Ensure, that levels are in order provided in the variable lvl.
lvs <- c( "none", "oncePerWeek", "severalPerWeek", "daily" )
sample( lvs, 3 )
[1] "severalPerWeek" "oncePerWeek" "daily"
sample( lvs, 3 )
[1] "daily" "severalPerWeek" "none"
sample( lvs, 3 )
[1] "none" "daily" "severalPerWeek"
sample( lvs, 100 )
Error in sample.int(length(x), size, replace, prob): cannot take a sample larger than the population when 'replace = FALSE'
v <- sample( lvs, 100, replace = TRUE )
w <- factor( v, levels = lvs )
w
[1] oncePerWeek none none severalPerWeek daily none severalPerWeek
[8] oncePerWeek daily daily none severalPerWeek none none
[15] severalPerWeek severalPerWeek none severalPerWeek oncePerWeek daily daily
[22] oncePerWeek severalPerWeek none severalPerWeek severalPerWeek daily severalPerWeek
[29] daily oncePerWeek oncePerWeek none none severalPerWeek daily
[36] none severalPerWeek none oncePerWeek severalPerWeek none oncePerWeek
[43] none severalPerWeek oncePerWeek daily daily oncePerWeek oncePerWeek
[50] daily oncePerWeek none severalPerWeek daily daily daily
[57] none severalPerWeek daily none none severalPerWeek oncePerWeek
[64] daily daily oncePerWeek none oncePerWeek daily oncePerWeek
[71] severalPerWeek oncePerWeek oncePerWeek none severalPerWeek severalPerWeek none
[78] oncePerWeek none oncePerWeek severalPerWeek none none daily
[85] severalPerWeek oncePerWeek severalPerWeek daily oncePerWeek daily daily
[92] severalPerWeek oncePerWeek daily daily oncePerWeek daily daily
[99] none oncePerWeek
Levels: none oncePerWeek severalPerWeek daily
fct_count( w )
# A tibble: 4 x 2
f n
<fct> <int>
1 none 25
2 oncePerWeek 25
3 severalPerWeek 24
4 daily 26
- Reordering factor levels.
When a factor is shown on an axis of a plot, the order is given by its levels.
The factor w from the previous exercise will be then shown in this order: none, oncePerWeek, severalPerWeek, daily.
But for a picture in a manuscript the following order might be needed: daily, severalPerWeek, oncePerWeek, none.
Apply to w one of the fct_ functions from the tidyverse library to produce a factor w2 with the requested order.
Show the levels of w2.
Again show the number of elements of each level in w2 and compare it with the table of the previous exercise.
w2 <- fct_relevel( w, c( "daily", "severalPerWeek", "oncePerWeek", "none" ) )
levels( w2 )
[1] "daily" "severalPerWeek" "oncePerWeek" "none"
fct_count( w2 )
# A tibble: 4 x 2
f n
<fct> <int>
1 daily 26
2 severalPerWeek 24
3 oncePerWeek 25
4 none 25